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MySQL error: Column count doesn't match value count at row 1

The problem is with this line:

String query = "insert into

The table ChampionData has 13 columns:


While the row you're trying to insert has only 12 columns (as evidenced by the 12 question marks)

Categories : Java

Related to : MySQL error: Column count doesn't match value count at row 1
get the total likes count and message count using mediaid/post id graph api/Instagram api and get isuser following you or not
Media endpoint returns the number of likes and comments for a media: Look for data.comments.count and data.likes.count in the JSON response.

Categories : Android
SQL Query to COUNT fields that match a certain value across all rows in a table
You can use conditional aggregation: SELECT SUM((CASE WHEN friendly = 0 THEN 1 ELSE 0 END) + (CASE WHEN professional = 0 THEN 1 ELSE 0 END) + (CASE WHEN comfortable = 0 THEN 1 ELSE 0 END) + (CASE WHEN rate = 0 THEN 1 ELSE 0 END) + (CASE WHEN recommend = 0 THEN 1 ELSE 0 END) + ) AS MatchZero, SUM((CASE WHEN friendly = 1 THEN 1 ELSE 0 END

Categories : SQL
How to count unique number of words using fgetc() then printing the count in C
Don't know if this is homework or not so I did not do everything for you, I also cleaned up your code a little bit. But pretty much if you don't have a knowledge of how many words the person may input you need a dynamic data structure such as a linkedlist #include <stdio.h> #include <string.h> #include <ctype.h> typedef struct linkedlist linkedlist; struct linkedlist{ char

Categories : C
Column count return zero The sqlite3_data_count(P) routine returns 0 if the previous call to sqlite3_step(P) returned SQLITE_DONE. Try putting the data count after your sqlit3_step statement (inside your while loop)

Categories : IOS
Self Join with Count in Mysql
I think the only trick here is that you need a left join to get the rows with zero count. Here is one way to write the query: select, t.fname, t.lname, count(t2.sponsor_id) as num_sponsored from table t left join table t2 on = t2.sponsor_id group by, t.fname, t.lname; An alternative approach doesn't use an explicit join: select t.*, (select count(*) from table t2 wher

Categories : Mysql
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