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issue counter and arrays

Yes, your solution is a good solution, so the steps are: (pseudocode)

LetterCount class: - has an array count[25]

Process func:

  • scan each char

  • if char -'a' is not a letter: continue

  • count[char - 'a']++ (actually 'a' stands for 97, is the ascii value)

Getcount func

  • return count[param.tolowercase - 'a']

Categories : Java

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Boolean Methods with Arrays, coding issue
To check whether you have two pairs, simply create a counter that increments every time you find a pair - instead of instantly returning true. If your counter ever reaches two, you return true. Also, your worries about two pairs and four of a kind being similar should all be handled outside these methods. As in, check to see if you have the most restrictive (or highest point) hand first, and only

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May I know why the counter is 1 and 4 for this code?
Starting with sort(a,4) npts =4 ... No. It doesn't have to be. You seem to be expecting sort(a,4) called first and then sort,6). The order of evaluation of arguments to printf() function is unspecified. That means, you don't know which one of sort(1,4 and sort(a,6) will be called first. Calling them one after another would give predictable result.

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unable to loop through a Counter in Swift
You're probably in an infinite loop here: do { if intervalCountdown > 0 { intervalHasBeenSet = true intervalCountdown-- IntervalTimer.text = String(format: "%02d:%02d", intervalCountdown/60, intervalCountdown%60) } } while intervalHasBeenSet == true Your condition is intervalHasBeenSet == true but it's never being set to false inside the loop, s

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Measuring runtime with counter variable
In this case, your number of exchanges is proportional to your number of comparisons. Also, your loc > 0 is what I'd consider an "incidental operation" as stated in that excerpt. So, assuming comparisons and movements are constant time operations (which they are for integers), you'll get the same trends in your data by simply incrementing your counter once each loop iteration.

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C++ compile time counter in macros
You may generate something like this: enum genericEnum { MY_ENUM_BASE=0, FIRST, PAST_FIRST= (FIRST<<1)-1, SECOND, PAST_SECOND= (SECOND<<1)-1, THIRD, PAST_THIRD= (THIRD<<1)-1, FOURTH, PAST_FOURTH= (FOURTH<<1)-1, }; using standard macroprocessor without using COUNTER, i.e. defining MAKE_ENUM as #define MAKE_ENUM(NAME) NAME, PAST#

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