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"Invalid operands to binary expression ..." when trying to compare regex_iterators

int main()
    int i = 0, f(int);

int f(int) {return 0;}

Is valid code. There is a block-scope function declaration of f inside main, in the same init-declarator-list as i, which is a usual int.

The same happens in your case, just in a more complicated manner. Here the function declared is regend and has a parameter of type std::regex_iterator<..> - you could have also deduced this by inspecting the error message.
The problem wouldn't be solved by using std::regex_iterator<std::string::const_iterator>(); Then the parameter would be a pointer-to-function instead, but regend not a variable.
Use uniform initialization (i.e. { and }) or double braces to avoid this.

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