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C++ Erasing element from a vector of pointers

You're deleting the account from a copy:

std::vector<T*> getDatabase ()

std::vector<Account*> db =

You need to delete from the actual database, so you want the usage to be:

std::vector<T*>& getDatabase
const std::vector<T*>& getDatabase ()

std::vector<Account*>& db =

Categories : C++

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Vector of class pointers
I'd have to see your init method, but my guess would be that your random function is using a seed value like the current time (eg in milliseconds since the epoch) to initialize itself, and your code is executing so quickly that the time hasn't changed between calls, so it returns the same random number.

Categories : C++
adding a element to an array of pointers within an object
It depends on the syntax of the language it self, but in C# you can do something like this. I believe you have similar syntax in other languages as well, which is basically you create a new array and populate it. saun.siblings = new Family [] {shannon, kailey, kyle};

Categories : Java
finding element in array then swapping using pointers
It's hard to help you without knowing how the elements are storred. Are they in a simple (c like) array ? Are they in a C++ stl containner like std::vector ? If they are in a simple c like array you can do template <typename T> bool findElement(T element, T* array, size_t size) { T* ptr = std::find(array, array+size, element); if (ptr == array+size) return false; std::swap(*arr

Categories : C++
Sum of element in Vector to get the correspond Matrix
You could think about the problem in a different way - essentially what you're calculating is the average of the distance between the start points of each facility and the end points of each facility. i.e. <------start dist------> [ A ][ B ][ C ][ D ] <--------------end dist--------------> You can calculate the start a

Categories : Matlab
Dividing first element of a column vector of dimension 3x1 with column vector of dimension 5x1 and so on in R
You could use outer c(outer(a,b, FUN="/")) #[1] 0.2500000 0.5000000 0.7500000 0.2000000 0.4000000 0.6000000 0.1666667 #[8] 0.3333333 0.5000000 0.1428571 0.2857143 0.4285714 0.1250000 0.2500000 #[15] 0.3750000 If you want it as fractions library(MASS) fractions(c(outer(a,b, FUN="/"))) #[1] 1/4 1/2 3/4 1/5 2/5 3/5 1/6 1/3 1/2 1/7 2/7 3/7 1/8 1/4 3/8 Or if you want to represent it like this c

Categories : R
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