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Getting out of scope error with dynamically allocated array


If you declare the variable inside the try block then it's only accessible there. You can work around this by moving the declaration outside of the block.

int *newArr;

try
{
    newArr = new int[els];
}
catch(const bad_alloc &)
{
    die("Alloc Failure");
}

for (int i = 0; i < els; i++)
    newArr[i] = a[i];

Or by moving the rest of the code inside the try.

try
{
    int *newArr = new int[els];

    for (int i = 0; i < els; i++)
        newArr[i] = a[i];

    return newArr;
}
catch(const bad_alloc &)
{
    die("Alloc Failure");
}

Categories : C++

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