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sorting dictionary values in python - descending alphabetically

You may use another data-structure, because you have duplicate keys. But in general you might consider this:

from operator import itemgetter
for i in sorted(higharr.items(),
key=itemgetter(1), reverse=True):
    print i

Categories : Python

Related to : sorting dictionary values in python - descending alphabetically
Sorting a dictionary of dictionary using values in Python
If you want order you need an OrderedDict of OrderedDicts, by chance the outer dict is in sorted order but normal dicts have no order: from collections import OrderedDict d = { 1: {2: 30, 3: 40, 4: 20, 6: 10}, 2: {3: 30, 4: 60, 5: -60}, 3: {1: -20, 5: 60, 6: 100}, } keys = sorted(d.keys()) # sort outer dict keys o = OrderedDict() for k in keys: # loop over the sor

Categories : Python
python: count values of dictionary
Not sure if this is what you're looking for? def getcountvalue(d): newdict = {} for key, value in d.items(): newdict[key] = len(value) return newdict d = {2: [(1, 1)], 3: [(2, 1), (2, 1)], 4: [(1, 3), (3, 1), (3, 1)], 5: [(1, 4), (2, 3), (2, 3), (4, 1)], 6: [(1, 5), (2, 4), (2, 4), (3, 3), (3, 3)], 7: [(1, 6), (2, 5), (2, 5), (3, 4), (3, 4), (4, 3)], 8: [(2, 6), (2, 6), (3, 5

Categories : Misc
Python: Calculate all values of dictionary to z-scores
assuming you use Scipy to calculate the Z-score and not manually from scipy import stats d = {'keys':values, ...} dict_values = d.values() z = stats.zscore(dict_values) This will return a Numpy array with your z scores

Categories : Python
How to copy unique keys and values from another dictionary in Python
Since you're using pandas, I should point out that the problem you're facing is common enough that there's a built-in way to do it. We call collecting "similar" data into groups and then performing operations on them a groupby operation. It's probably wortwhile reading the tutorial section on the groupby split-apply-combine idiom -- there are lots of neat things you can do! The pandorable way t

Categories : Python
python dictionary creating keys on letters and values on frequency it appears
Simply pass the whole string to a collections.Counter() object and it'll count each character. It may be more efficient to do so line by line, so as not to require too much memory: from collections import Counter counts = Counter() with open('inputtextfilename') as infh: for line in infh: counts.update(line.strip()) The str.strip() call removes any whitespace (such as the newline

Categories : Python
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