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How to take a string and return a list of all the words in a dictionary that differ from this word by exactly one letter?


I guess you shouldn't reinvent the wheel. There is a good python library that implements the Levenstein distance metric. I think you'll find it useful.


Categories : Python

Related to : How to take a string and return a list of all the words in a dictionary that differ from this word by exactly one letter?
How to find lines including two letter words using grep
You can use the "word mode": $ cat file.txt A AB CDE ABD KJSD SD DAD LD $ grep -w '..' file.txt A AB CDE SD DAD LD From man grep: -w, --word-regexp Select only those lines containing matches that form whole words. The test is that the matching substring must either be at the beginning of the line, or preceded by a non-word constitu

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A dictionary mapping words to lists of objects
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Replace specific letter in string
This could be easily done like this: var string = "dynamic_fields[n][key]"; var replaced = string.replace(/[n]/,"[1]"); alert(replaced); Basically, this finds the character "n" that is surrounded with brackets, and replaces it with a "1" surrounded with brackets. Remeber to "escape" the brackets to make them literal. https://developer.mozilla.org/en-US/docs/Web/JavaScript/Guide/Values,_var

Categories : Javascript
letter frequency from a string in a file using python
If you want the count of all the letters in the file use a collections.Counter dict: from collections import Counter c = Counter() with open("input.txt") as f: for line in f: c.update(line.split(",")[0]) print(c) Counter({'e': 16, 'r': 12, 'd': 8, 'a': 6, 't': 6, 'n': 4, 'q': 4, 's': 4, 'u': 4, 'w': 4, 'i': 2, 'o': 2, 'p': 2}) To get total just multiply by the times it appears:

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Regex to validate string having only lower case, first char must be a letter
Why don't you just stick to your requirements ? first char must be a lowercase letter: [a-z] remaining characters must match: [a-z0-9_.] -> your regex: /^[a-z][a-z0-9_.]*$/

Categories : Ruby
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