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how many letter occur in a text?

What you'd want to do is remove the whitespace from the string before you count the letters;

Removing whitespace from strings in Java

Categories : Java

Related to : how many letter occur in a text?
why occur one desfase between JSF action calls?
I found a workaround, In view.xhtml I removed the action attribute of h:commandLink and add a f:actionListener tag after the f:setPropertyActionListener (order matters) <h:commandLink target="_blank"> <f:setPropertyActionListener target="#{documentBean.selectedDocument}" value="#{document}" /> <f:actionListener binding="#{documentBean.openDocumentActionListener}" />

Categories : Java
Will deliver event if configChanges occur or if activity in background?
The Activity will obviously not receive any events between unregister() in onDestroy() and register() in onCreate() - remember that by default the Activity will be fully recreated when configuration changes. However, if you registerSticky() then you'll have access to the latest published event, even if it arrived at the moment of Activity recreation.

Categories : Android
Removing letters from a string that occur in the previous string
You can use str.translate and str.maketrans for this: >>> def remove_letters(str1,str2): ... return str2.translate(str.maketrans('', '', str1)) ... >>> remove_letters('abc', 'aaabbbccc') '' >>> remove_letters('abc', 'aaaxbbbycccz') 'xyz' >>> If you test this solution with timeit.timeit, you will see it is quite efficient: >>> from timeit import

Categories : Python
php: How to ignore letter case within a preg_replace?
Add the case insensitive modifier, i, to the regular expression. function bold($text, $str) { // This fails to match if the letter cases are not the same // Note: I do not want to change the returned $str letter case. return preg_replace('/('.str_replace(array("/", "\"), array("/", "\"), $text).')/i', "<strong>$1</strong>", $str); }

Categories : PHP
Replace specific letter in string
This could be easily done like this: var string = "dynamic_fields[n][key]"; var replaced = string.replace(/[n]/,"[1]"); alert(replaced); Basically, this finds the character "n" that is surrounded with brackets, and replaces it with a "1" surrounded with brackets. Remeber to "escape" the brackets to make them literal.,_var

Categories : Javascript
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