|Related to : C - Help printing a member of a returned Struct|
|print member of struct of a vector|
Boost Adaptor adapts ranges, not single iterators. Similarily, the
boost::copy algorithm expects two arguments, where the first one is a
range, and the second an output iterator. Having said that, the
correct syntax for extracting a single data member from a range, and
copying it to an output iterator is:
|Access struct member from pointer|
As said by barak manos, your problem lies in init. C pass parameters
by value so let's imagine :
you set a pointer to pile to NULL (pile *p = NULL;)
you pass it to init (init(p);)
in init you alloc a pile and affect is to the local copy of p
on return from init, p is still NULL and you have a memory leak since
you have no longer any pointer to the allocated pile
That's the reason why you shoul
|Compile Error, Member is not a member of a union | working with pointers/structs|
line 74 was corrupted: instead of void convertStringToTime(char *
strTime , TTime * Zeit) it had to be void convertStringToTime(char *
strTime , TTime * lp). anything else seems to be fine.
Will try to get the memory allocation done now and look at strtol() as
an alternative solution.
|Template Member function cannot see non-templated class member correctly|
Check your default constructor, copy constructor, and any other custom
constructors/move/operator functions you write/overload. Make sure
these are doing what you think they are doing.
Templated functions work just fine in non-templated classes. Data
being inaccurate or missing is most likely a copy issue.
Edit: As pmr mentions below... Obey the rule of five. That is
definitely the main point.
|Const struct assigned to struct|
It is not the same. You are trying to assign const pointer to a non
const pointer. Another words: trying to assign Mutable pointer to a
constant StudentType to a non-const pointer.
It does make sense to change something that is declared const to
no-cont, meaning you could change a value of a constant.
What you are trying to do is to copy one object to another using
shallow copy. in order to do so