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How to make a result like this?


You can obtain it with a countdown loop and str_repeat

for($i=5; $i>=1; $i--){
    echo str_repeat("*", $i) ."<br>";
}

Categories : PHP

Related to : How to make a result like this?
How can I incrementally count the values of an sql result set column in the same result set?
Try this: SELECT "service request"."SR #" saw_0, "- contact communication"."Mobile Phone #" saw_1, row_number() over(partition by "- contact communication"."Mobile Phone #" order by "service request"."SR #") saw_2 FROM "service requests" WHERE ( "service request dealer"."Local Dealer Number" = '20536' ) AND ( "- cont

Categories : SQL
awk script to print in between result before the final result
I would go for something like this: awk 'NR==1 {next} {a[$1]+=$2} END {for (i in a) {print i, a[i]; tot+=a[i]} print "TOTAL", tot}' file For your given input it returns: 20140201 -362.9 20140202 -210 20140203 132 TOTAL -440.9 Explanation NR==1 {next} skip the first line. {a[$1]+=$2} for every line, keep an array containing a[day]=value. END {} when finished, print the

Categories : Bash
Keep getting -2147483647 as result
In your for loop, you are adding 1 to the result of a call to minNumber. When bigNumber is less than zero, the method returns int.MaxValue int.MaxValue + 1 == int.MinValue I'll leave it to you to step through the code, but in the first loop, when bigNumber is 5, you continue to do a recursive call, subtracting array[0] (which is 1) from it. This continues until bigNumber is 0, when the method

Categories : C#
error in sql query result
try this: For There is already an object named '##temp' in the database. Before Creating New Temp Table You need to Use This: if (object_ID('tempdb..##temp')) is not NULL DROP TABLE ##temp You need to add [Name],[ImageAddress],ID these columns to get desire output SET @Base = 'WITH Base AS (SELECT [Name],[ImageAddress],ID,COUNT(ID) CntID, ROW_NUMBER() OVER (ORDER BY Id DESC) RN FROM'

Categories : SQL
SQL query to display result
select product, type1 as type, manufacturer from the_table union all select product, type2, manufacturer from the_table union all select product, type3, manufacturer from the_table order by product, type;

Categories : SQL
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