Home PHP C# C++ Android Java Javascript Python IOS SQL HTML Categories

Given string x,y and z. Determine if z is a shuffle

You're right.

You never, ever HAVE TO use recursive algorithms. You're free to do so, but you can ALWAYS use an interative routine.

In this example, you could use arrays or allocate a memory block large enough to hold the result.

Categories : Algorithm

Related to : Given string x,y and z. Determine if z is a shuffle
determine string index
JOIN and INNER JOIN are redundant. You really just need an array like this: {"INNER JOIN", "LEFT JOIN", "RIGHT JOIN"} And once you have that, you'll notice that you always use the word join, and so you can change your code to always supply that part and only look for the first part in an array like this: {"INNER", "LEFT", "RIGHT"} At this point, your index lookup becomes much simpler.

Categories : Vb.Net
what's the most efficient way to shuffle huge bit-vectors using GCC
you could try rolling your own loop -- int ch1, ch2; while ((ch1 = fgetc(fp1)) != EOF && (ch2 = fgetc(fp2)) != EOF) { int i, dst = 0; // assuming msb goes first for (i=7; i>=0; i--) { dst |= (ch1 & (1<<i)) << (2*i + 1); dst |= (ch2 & (1<<i)) << (2*i + 0); } putc(dst >> 8); putc(dst & 0xFF); } You can ma

Categories : C++
Uniformly shuffle 5 gigabytes of numpy data
The following assumes your data is already divided into easily-retrievable records of some sort. (I don't know if there's a standard file format for numpy data.) Create an index of the data in the form of a dict, mapping each unique record ID (0 through n - 1) to some means of finding the data again. For instance, if it's all in one binary file, you'd store a tuple of the form (file_offset, re

Categories : Python
How to create a looping shuffle method in an array
The shuffle method will look like this : private void shuffle() { Deck ob = new Deck(); int x = deck.size() - 1; for(int i = 0; i < TIMES_TO_SHUFFLE + 1; i ++){ int r1 = (int) Math.floor(Math.random() * x); int r2 = (int) Math.floor(Math.random() * x); ob.swap(r1, r2); } }

Categories : Java
Algorithm of array shuffle with distance restriction
Here's some pseudo code that may help. Note that the algorithm is focused on conforming to the distance rule, sacrificing uniformity* in the process. choose a random array index (call it "i" ) there's number at array[i] (call it "A") set "count" to 0 for each "j" such that array[j] is a valid location for "A" { there's a number at array[j] (call it "B") if ( "B" can be legally moved to

Categories : Arrays
Recently Add
To find three unique numbers whose number of occurrence is even
Dealing with duplication between unit and integration tests
reflection and symmetry in back tracking queens
Big O analysis for method with multiple parameters
Divide Huge Array of Numbers in Buckets
Algorithm to find adjacent cells in a matrix
Why this code gives WA for Petersen Graph(codechef)?
Complexity of this prime number search algorithm
How to detect if a file has changed?
Given string x,y and z. Determine if z is a shuffle
Basic decryption for simple encryption algorithm
An efficient way to assign user_ids to huge dataset under certain conditions
What's a more efficient implementation of this puzzle?
Generating prime numbers in poly-time
What if I do not use G transpose in calculating Strongly Connected Components?
Dividing an array into optimum no of equal sum sublists
Counting derangements
How to iterate through all cases when partitioning objects
Algorithm: How to find closest element, having coordinates and dimension
Developing player rankings with ELO
How to transform two set of discrete points ( vectors ) to help plotting them on a common scale
Heap Sort Space Complexity
complex root finding algorithm
Every possible combination algorithm
RSA Cryptosystem - Retrieve m
Heap-like data structure with fast random access?
How do you pin point the location of a user with 3 nodes, using Triangulation?
Run time of reversing the words in a string
Depth First Search Algorithm Prolog
Algorithms for dividing an array into n parts
© Copyright 2017 Publishing Limited. All rights reserved.