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XSLT - get value of all nodes with the same name

Either you need to use an XSLT 2.0 processor like Saxon 9 or XmlPrime and make sure your stylesheet has version="2.0" as in that case you should get both values or with an XSLT 1.0 processor you need to use <xsl:for-each select="PRICES//PRICE_DATE"><xsl:value-of select="."/></xsl:for-each> respectively <xsl:apply-templates select="PRICES//PRICE_DATA"/> to make sure all selected nodes are processed and output. With XSLT 1.0 the xsl:value-of element only outputs the string value of the first selected node.

Categories : Xml

Related to : XSLT - get value of all nodes with the same name
How to loop through XML nodes and child nodes using JavaScript?
Attaching the root of your loop on employee rather than name would be better for nested loops (which is what this solution will use): var employees = xmlDoc.getElementsByTagName("employee"); //outputs array of employees for (employeeIndex = 0; employeeIndex < employees.length; employeeIndex++) { var empDetails = employees[employeeIndex].children; //outputs array of details for (deta

Categories : Javascript
XSL - Check nodes at the same level
Use the XPath axes, parent should work in this case: <xsl:if test="count(parent::*/*) &gt; 0">...</xsl:if> Select the parent node: parent::* Select all elements nodes inside the parent node: parent::*/* Count them and check here are more then zero: count(parent::*/*) > 0 * will return any element node, but not text node. You can use the element node name to select specifi

Categories : Xml
Reading XMl Data same nodes in C#
If you want the list of addresses then you can get the elements directly. Then you have to assign the values based on your criteria XElement elem = XElement.Parse(xmldata); IEnumerable<XElement> addresses = elem.Descendants("streetAddress"); Now you can loop through this and assign the values.

Categories : C#
Referencing to different sibling nodes
I don't know of any way of doing a destructuring bind with XSL; I'd be interested to know if there is a native idiom for that. Anyway: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl=""> <xsl:template match="/row"> <row> <xsl:for-each select="table[@name='Person']/tuple/val"> <xsl:variab

Categories : Xml
How to get index of all the nodes in a TreeView?
The following method allows you to traverse through a tree: public static IEnumerable<T> Traverse<T>( this IEnumerable<T> source , Func<T, IEnumerable<T>> childrenSelector) { var stack = new Stack<T>(source); while (stack.Any()) { var next = stack.Pop(); yield return next; foreach (var child in childrenSelector(next))

Categories : C#
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