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Please Try this.

SUM(price) AS 'price',
    tbl_expense e
INNER JOIN tbl_gasoline g ON e.GasolineType =

Categories : SQL

Sprade distinct values over a different columns
It can be done with dynamic sql declare @query varchar(max); declare @values varchar(max) = null; with distinctValues as ( select distinct cast(value as varchar(20)) as value from myTable ) select @values = COALESCE(@values + ', ['+ value + ']', '['+ value + ']') from distinctValues; set @query = 'select [id], ' + @values + 'from myTable pivot ( count(value) for value in (' + @values + '))

Categories : SQL
Set certain values in column B by matching it to another pair of columns
In the first sheet, use a VLOOKUP function to find corresponding matches in the second sheet (I'll call that Sheet2. with IFERROR to catch no matches. In the first sheet's B2 cell, use this formula, =IFERROR(VLOOKUP($A2, 'Sheet2'!$A:$B, 2, FALSE), "") VLOOKUP function That will return the first value in column B that corresponds to a matching value in column A which seems to be what you want.

Categories : Excel
Select sets of values from R matrix column
Try H[cbind(seq_len(nrow(H)), P)] ## [1] 0.6733731 0.7396847 0.5953580 Here we are indexing by consecutive rows and columns indicated in P Regarding your question, so the reason H[, P] returns a matrix is because you are telling R: select all rows in columns: 2, 1, 2 from matrix "H" thus the result that you are getting is a matrix with identical first and third columns.

Categories : R
Extending the result set adding columns taken from another table's distinct rows
Something like SELECT,, (SELECT COUNT(c.uid) FROM CHOICE WHERE c.kname = 'city1') AS city1, (SELECT COUNT(c.uid) FROM CHOICE WHERE c.kname = 'city2') AS city2, (SELECT COUNT(c.uid) FROM CHOICE WHERE c.kname = 'city3') AS city4, (SELECT COUNT(c.uid) FROM CHOICE WHERE c.kname = 'city4') AS city4 FROM USER u INNER JOIN CHOICE c ON = c.uid GROUP BY,

Categories : Mysql
Compare Column A to Column B and copy items that are in both columns into Column C
You can use =IF(RIGHT(A1,LEN(A1)-FIND(".",A1))=RIGHT(B1,LEN(B1)-FIND(".",B1)),RIGHT(A1,LEN(A1)-FIND(".",A1)),"No") =RIGHT(A1,LEN(A1)-FIND(".",A1)) will return from a cell even if it starts with http:// or http://www. or www. The above formula just compares the website from each column and if it is a match, it will return the website, otherwise return "No"

Categories : Excel
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