|Related to : How to generate 6 months average spend prior current date|
|How to add 60 months to current date in data stage jobs?|
this issue is there in datastage till FP8.x version. This issue is
fixed in later versions. If you want to work in older versions, you
need to install patch given by IBM to fix this or you need to write
your own logic to get the date after adding months.
|SQL - Months and Dates|
Ok, I don't know VectorWise or how ansidate is stored, however, if
it's stored as an integer value I assume it represents a certain
amount of time, measured on a specific time unit since a starting time
If it's true, you can convert your 3 months to the time unit in which
ansidate is being stored and add the converted value.
|How to get months and days between two date|
i think directly u can not get like z day y hr x min
but you can get separate day min sec and all like below -
long diff = EFFDAT.getTime() - CURRDATE.getTime();
long diffSeconds = diff / 1000 % 60;
long diffMinutes = diff / (60 * 1000) % 60;
long diffHours = diff / (60 * 60 * 1000);
int diffInDays = (int) ((dt2.getTime() - dt1.getTime()) / (1000 *
60 * 60 * 24));
|Subset in R between 2 Months over a Range of Days|
As @JoshuaUlrich said, the month of one observation can't be two
values at the same time.
Something like that would work:
vf1 <- vf [ which( vf$Month==4 & vf$Day>19 | vf$Month ==5
& vf$Day <32 ), ]
So you are saying if Month is 4, Day must be larger 19 or if Month is
5, Day must be smaller 32.
|perl datetime add months fails in dst timezone|
Your solution is recommended in the documentation, so it should be OK.
Also, when I ran your original code, I got an error back:
Invalid local time for date in time zone: America/Sao_Paulo