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Xslt: How to change node text in element using a parameter


You've got to remove the attribute xpath-default-namespace="http://www.tei-c.org/ns/1.0" from xsl:stylesheet element. This attribute applies the mentioned uri as the namespace uri to all elements in xpaths, by default.

Example: If you run the following XML(a part from your input):

<entry>
<form type="hyperlemma" xml:lang="cu">
     <orth>value</orth>
</form>
</entry>

against this XSLT:

<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xpath-default-namespace="http://www.tei-c.org/ns/1.0"
version="2.0">
<xsl:output method="text" indent="yes" />
<xsl:param name="replace_orth"
select="entry/form[@type='hyperlemma' and
@xml:lang='cu']/orth" />

<xsl:template match="/">
    <xsl:value-of select="$replace_orth"/>
</xsl:template>
</xsl:stylesheet>

The output is nothing. The reason is all the xpath elements, by default, are supposed to have the namespace http://www.tei-c.org/ns/1.0. Thus teh param, replace_orth, selects nothing as the input XML doesn't have that namespace for any of its elements.

But, if you change your input XML to the following:

<entry
xmlns="http://www.tei-c.org/ns/1.0">
<form type="hyperlemma" xml:lang="cu">
     <orth>value</orth>
</form>
</entry>

The output will be: value

And that's because the default namespace for all the elements in the input XML is http://www.tei-c.org/ns/1.0


Categories : Xml

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