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get node and value if it's not null using Xslt
You could do something like this: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output indent="yes"/> <xsl:strip-space elements="*"/> <xsl:template match="*[text()]"> <xsl:copy-of select="."/> </xsl:template> </xsl:stylesheet> Depending on input, like if there was more than one element tha

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XSLT group dynamically generated nodeset
I've had a difficult time trying to group using keys a la muenchian since match doesn't allow variables: You do not need to use a variable in the match definition. Define your key element as: <xsl:key name="row-by-site" match="row" use="col[@column-label='Site']"/> You must be in the context of the "document" created by the query when calling the key() function - otherwise it will

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XSLT replace options
Your input is not valid, instead of <select>id="USE-THIS-ID-IN-XSLT"> it should be <select id="USE-THIS-ID-IN-XSLT">. With this correction, following XSLT <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="html" indent="yes" /> <xsl:strip-space elements="*"/> <

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XSLT Transform UL to SELECT
It is straight-forward with templates: <xsl:template match="ul"> <select> <xsl:apply-templates/> </select> </xsl:template> <xsl:template match="li"> <option value="{@value}"> <xsl:apply-templates/> </option> </xsl:template>

Categories : Xslt

XSLT templates' ambiguity clarification
Your result is due to implicit template priorities. You can explicitly specify a priority on any template: <xsl:template match="foo" priority="2"/> But in most cases, you do not state explicitly what priority you would like a template to adopt - and that's where the default priorities step in. If there is conflict between templates, that is, if an input node matches several templates, XSL

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How can I use XSLT with non-traditional XML formatting?
Use sub-selectors: <td><xsl:value-of select="FIELD[@fname='Description']"/></td> and so one. You could also consider pre-processing the XML to a more regular format.

Categories : Xslt

while loop with different parameter in query
Though not sure about the wanted output, just an example as suggestion in case I understand the requirement right: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output omit-xml-declaration="yes" indent="yes"/> <xsl:template match="dbqueries"> <xsl:apply-templates select=".//row" mode="while"> <xsl:with-param name="r

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Split XML nodes based on particular text
[groan] Where do you find these "interesting" tasks? You should NEVER be required to form XML nodes manually, using escaped text. Try the following stylesheet. It could probably be more streamlined, but I believe it addresses the main issue here: XSLT 2.0 <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" version="1.0" encoding="U

Categories : Xslt

BizTalk XSLT + If not equal is not working
Check the condition <xsl:if test="($s0_PolicyNumber != $s1_PolicyNumber) or (s0_EffectiveDate != $s1_EffectiveDate) or (s0_CommPercent != $s1_CommPercent) or (s0_CommAmount != $s1_CommAmount) or (s0_PremiumAmount != $s1_PremiumAmount)"> "$" is missing in some places.

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How to write XSLT test condition with two functions
Do two things: (a) check the spelling of your function names (b) find out why you aren't getting any proper diagnostics. You're either using an XPath engine with particularly bad diagnostics, or you aren't running it properly.

Categories : Xslt

Creating a list using xslt
Following XSLT <?xml version="1.0" encoding="UTF-8" ?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="xml" omit-xml-declaration="no" encoding="UTF-8" indent="yes" /> <xsl:template match="Employee"> <ArrayOfstringVariable> <xsl:apply-templates select="*"/> </ArrayOfstringVariable&

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Store XML fragment into attribute as string using XSL
With XSLT 3.0 there is a function serialize-xml, in earlier versions you can import a module like http://lenzconsulting.com/xml-to-string/ and then code <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:import href="xml-to-string.xsl"/> <xsl:template match="/"> <xsl:apply-templates/> </xsl:template> <xsl:template match="

Categories : Xslt


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get node and value if it's not null using Xslt
XSLT group dynamically generated nodeset
XSLT replace options
XSLT Transform UL to SELECT
XSLT templates' ambiguity clarification
How can I use XSLT with non-traditional XML formatting?
while loop with different parameter in query
Split XML nodes based on particular text
BizTalk XSLT + If not equal is not working
How to write XSLT test condition with two functions
Creating a list using xslt
Store XML fragment into attribute as string using XSL
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