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VBA remove matching first & last names across 2 worksheets
Loops through all values in Sheet1 Column B. If that value is found in Sheet2 Column E, the entire row in Sheet1 is deleted. Then it loops through all values in Sheet1 Column C. If that value is found in Sheet2 Column F, the entire row in Sheet1 is deleted. Sub DeleteCopy() Dim LastRow As Long Dim CurRow As Long Dim DestLast As Long LastRow = Sheets("Sheet1").Range("B" & Rows.Count).End(

Categories : String

Create a self updating string based on files in a folder in Processing
Assuming you're using this in Java mode, then you can use the Java API: https://docs.oracle.com/javase/8/docs/api/ The Java API contains a File class that contains several methods for reading the contents of a directory: https://docs.oracle.com/javase/8/docs/api/java/io/File.html Something like this: ArrayList<String> songs = new ArrayList<String>(); File directory = new File("path/

Categories : String

Scala strings - how to change lines
The more idiomatic scala way to do it would be to not do several things at once and also mutate state, but instead see it as separate operations/expressions. Something like this for example: val sortedResults = result.sortBy(_._3 match { case "FirstTest" => 1 case "SecondTest" => 2 case "ThirdTest" => 3 }) val reportLines = sortedResults.map(result => createReport(result._3))

Categories : String

Haskell - How to concatenate a String to a list of Strings
Type annotations: r :: String p :: String ps :: [String] -- We need to produce a [String], not a String (++) :: [a] -> [a] -> [a] (++) :: String -> String -> String -- Because String = [Char] (:) :: a -> [a] -> [a] "Not " ++ r ++ " Or " :: String ("Not " ++ r ++ " Or ") : ps :: [String] This process should guide you to a correct implementation. Work through the types carefu

Categories : String

Hashcode of String new () objects showing same values
That's normal. A hash is an algorithm based on an input always having the same output. It is by no means a random generator. If you want them to be different, the string values should be unique. You can also add a value like an ID to the hash, so that s2 would be Canada, but when you hash it, you hash Canada-s2. that's a unique string, so you would get a unique output.

Categories : String

deleteCharactersInRange - Swift
In light of DarkDust's answer, we can make a very Swift-like extension that will make removeRange easier to use (and it's probably better than going back and forth between an NSMutableString): extension String { mutating func deleteCharactersInRange(range: NSRange) { let startIndex = advance(self.startIndex, range.location) let length = range.length self.removeRange(Ra

Categories : String

Check multiple rangeOfString (Swift)
You could just add a check if the string is non-empty: if checker2 != "" && string2.lowercaseString.rangeOfString(checker2) != nil { println("exists2") } But that is actually not necessary because rangeOfString() returns nil if called with an empty argument. And if you rewrite the test as if string2.rangeOfString(checker2, options: .CaseInsensitiveSearch) != nil { println("exis

Categories : String

VB6 string variable truncating data that it reads from a file
The easiest way to read in a whole file into a string is the following: Dim intFile As Integer Dim strFile As String Dim strData As String strFile = "c: empfile.txt" intFile = FreeFile Open strFile For Input As #intFile strData = Input(LOF(intFile), #intFile) Close #intFile If you want you can then split the data into an array of lines as follows: Dim strLine() As String strLine = Split(strD

Categories : String

assembly find words that contain substring in given string
The next instructions are not correct. "mov ebx,[esp+16];" "mov eax,[esp+12];" Use EBP in stead of ESP to process your parameters. This syntax does not exist. What do aim to accomplish? "mov [ecx,esp+8];" What do you think the jz reset will act upon? The ZF defined after cmp dl,dh is destroyed by inc ebx. "cmp dl,dh;" "inc ebx;" "jz reset;"

Categories : String

How to compare strings in golang?
You mean like this. Please note, this will not handle UTF 8, only ascii. package main import ( "fmt" ) func equal(s1, s2 string) int { eq := 0 if len(s1) > len(s2) { s1, s2 = s2, s1 } for key, _ := range s1 { if s1[key] == s2[key] { eq++ } else { break } } return eq } func main() { fmt.Println(equal("buz

Categories : String

Swift is there a method that gives the index of a substring inside another string
You can use the rangeOfString method: import Foundation let word: String = "Hey there, how are you?" if let range = word.rangeOfString("ere, how are") { let index = distance(word.startIndex, range.startIndex) println("index = (index)") } It returns a range, i.e. both sides of the searched string - just use the startIndex property. Note that this is a method borrowed from NSString

Categories : String

Grooviest way to join collection of Strings in Groovy 2.x
You need to use the Iterable or Iterator<Object> version of join: join(Iterator<Object> self, String separator) instead of join(Collection self, String separator). This is the only variety of join which is deprecated. join(Iterable self, String separator) and join(Object[] self, String separator) are few more which are in use.

Categories : String

Lua Pattern Exclusion
You can't do this with one capture, but it's trivial to splice the results of two captures together: local first, last = string.match(code, "(%d+)%-%d+%-(%d+)") local newid = first .. "-" .. last If you're trying to match against a list of patterns, it may be better to refactor it into a list of functions instead: local matchers = { function(s) return string.match(s, "^(%d+)") end, fun

Categories : String

Input must be a string MATLAB ERROR when using cellstr(sentiment)
You don't need the curly brackets around whatever you're assigning into a cell. The assignment is exactly symmetric to reading out the value: s = sentiment{i}; sentiment{i} = s(15:22); Surrounding a value with {} actually creates a cell array, which is why you appear to have a subcell. To help understand this difference between () and {}, try this: sentiment(i) = {s(15:22)}; Same result!

Categories : String

Removing rows in a cell array without a specific word
Logical indexing, and =[] for deletion. Guessing from the strfind documentation (cannot try at the moment), probably like this: isabsent = cellfun(@isempty,IDX); datesent(isabsent)=[];

Categories : String

String into Enum c++
What you actually need to do is flip your std::map around so it maps string to enum rather than enum to string. Then, you can do xmap[string] and get your enum. So you can do std::map<std::string, tEnumCouleur> xmap = boost::assign::map_list_of<std::string, tEnumCouleur>(A, "A")(B, "B")(C, "C"); and then you can simply do xmap["BLACK"] and you'll get the enum value BLACK

Categories : String

print to string or convert AnyObject to string swift Azure
Okay, i find solution: If some tyype you can print, but don't know what it is - object implementation Printable interface(printable) So, you can do that: var t:String = result.description And all, good day

Categories : String

Convert string to Foo (type string)
Convert c to Foo directly. f = Foo(c) Playground: http://play.golang.org/p/WR7gCHm9El Edit: This works because Foo is a string underneath. Foo is a new and distinct derived type; its base type is string. You can similarly make derived types for any existing type. Each derived type is distinct, so you get type safety. Conversions must be explicit.

Categories : String

How to check whether a input string is a File name or Folder name using Vbscript
Check whether the user input refers to an existing file (.FileExists) or folder (.FolderExists): If FolderExists(userinp) Then folderaction Else If FileExists(userinp) Then fileaction Else handle bad user input End If End If If that doesn't fit your needs, ask the user to identify folders by always appending "" and check Right(userinp, 1).

Categories : String

SPSS replace missing values
The dialogue you are discussing is for imputation techniques for missing data. Such as the mean or the median of the series or nearby points (the specific command is RMV) and so it is only applicable for numeric data. One way to replace missing values for string variables is to use the RECODE command, example shown below. DATA LIST FREE / X (A5). BEGIN DATA A B ? C ? END DATA. MISSING VALUES X

Categories : String

Vim replace all characters up to first comma
This should do it: [esc]:%s:^[^,]*,:: edit: of course you can also use cut: cut -d , -f 2- < mybigfile.txt > newfile.txt

Categories : String

Can't seem to add char read from file to string buffer
I suspect DS and ES aren't correctly initialised at all. Following test case works here fine (I didn't change your functions): .MODEL small .STACK 1000h .DATA SBUFFL DB 40 DUP ('x'),'$' FHANDLE DW ? CBUFF DB ? sample_txt db 'sample.txt',0 errtxt db 'Error.', 13, 10, '$' .CODE main PROC mov ax, @data ; Initialise DS & ES mov ds, ax mov es, ax mov ax

Categories : String

Haskell: returning strings that are before & after a given string
You have two syntax errors in this code. First, you have an extra | at the end of your Positions type. I like to write my ADTs a bit differently so that it's easier to see when I've messed up: data Positions = First | Second | Third | Fourth | Fifth The other error is that you seem to have copy/pasted some non-ascii quote characters into your source around each of the firs

Categories : String

Matlab cells with Names
Your question is pretty much fully covered in the docs to the save() command under "Save Structure Fields as Individual Variables". To get there, you only must create that struct. To create that struct(), where you dynamically create its field names, not much of your code must be changed. Once your struct is created in that loop, just save the struct once after the loop with the option '-struct',

Categories : String

loops & string processing error due to logical flaw - python
Your problem lies in your if/if/else conditions: if 'open source' in str(item).lower(): tags.append('open source') if 'data science' in str(item).lower(): tags.append('data science') else: item = str(item).lower().split(' ') tags.extend([e.strip("'():,&;+?][ ") for e in item if e not in remove] Suppose item is 'open source' then you will go through the first if and append 'o

Categories : String

int object is not iterable?
For every key check its value like this: for key in count: if count[key] == 1: print(key,"occurs one time") else: print(key,"occurs",count[key],"times") count.values() method returns only values in dictionary not keys. count.items() will return you key value pairs.

Categories : String

Splitting string into substrings in Lua
Your first loop does find four matches. Try this to confirm: for word in string.gmatch(content, '###([^#]+)') do print(word) end If that works for you, then save word in the loop as needed.

Categories : String

word counter on middle words in string
Your error comes when the user enters single name and the first and last index becomes same.I don't think you need a loop for for count.Try this code: public static void main(String args[]) { Scanner sc = new Scanner(System.in); boolean flag = true; while (flag) { System.out.print("Enter full name (at least 2 words): "); // reads from the keyboard t

Categories : String

swift xcode string to decimal number
je parlais Français très mal... let str : NSString = xA.text var xa : Float = str.floatValue var xa1 : Double = str.doubleValue // or let formatter = NSNumberFormatter() formatter.numberStyle = NSNumberFormatter.DecimalStyle var xa2 : NSNumber? = formatter.numberFromString(str)

Categories : String


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